-16x^2+80x+200=0

Solution for -16x^2+80x+200=0 equation:

-16x^2+80x+200=0

a = -16; b = 80; c = +200;
Δ = b2-4ac
Δ = 802-4·(-16)·200
Δ = 19200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19200}=\sqrt{6400*3}=\sqrt{6400}*\sqrt{3}=80\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-80\sqrt{3}}{2*-16}=\frac{-80-80\sqrt{3}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+80\sqrt{3}}{2*-16}=\frac{-80+80\sqrt{3}}{-32}
$